3p^2-47p-16=0

Solution for 3p^2-47p-16=0 equation:

3p^2-47p-16=0

a = 3; b = -47; c = -16;
Δ = b2-4ac
Δ = -472-4·3·(-16)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-49}{2*3}=\frac{-2}{6}
=-1/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+49}{2*3}=\frac{96}{6}
=16
$